[Netkit.users] Link A - B - C

Alpt alpt a freaknet.org
Ven 25 Mar 2005 11:59:04 CET

Hi there,
I need to reconstruct with netkit the following topology:
       A(eth0) -- (eth0)B(eth1) -- (eth0)C

B must have only one ip.
The purpose of this is having an ad-hoc network were 
A is directly linked with B and B with C, but A doesn't see C.

I'm trying with:
$ vstart pc1 --eth0=A $X
$ vstart pc2 --eth0=A --eth1=B $X
$ vstart pc3 --eth0=B $X

pc3# ifconfig eth0
pc1# ifconfig eth0
pc2# /sbin/brctl addbr br0
     /sbin/brctl addif br0 eth1
     /sbin/brctl addif br0 eth0
     /sbin/ifconfig eth0 promisc up
     /sbin/ifconfig eth1 promisc up
     ifconfig eth0 hw ether 00:00:00:00:00:06
     ifconfig eth1 hw ether 00:00:00:00:00:07
     /sbin/ifconfig br0 up

But this doesn't work at all.

Any hints?

Best Regards
"I don't know nothing" The One Who reached the Thinking Matter   '.'

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